Use the following data to calculate the enthalpy of hydration for caesium iodide and caesium hydroxi — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

The equation relates: $\Delta H_{\text{solution}} = \text{Lattice Energy (LE)} + \Delta H_{\text{hydration}}$. Re-arranging gives $\Delta H_{\text{hydration}} = \Delta H_{\text{solution}} - \text{LE}$. For CsI: $33 - 604 = -571\text{ kJ/mol}$. For CsOH: $-72 - 724 = -796\text{ kJ/mol}$.