Enthalpy of neutralization of by NaOH is –106.68 kJ/mol. If the enthalpy of neutralization of HCl by — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

Phosphorous acid ($\text{H}_3\text{PO}_3$) is strongly dibasic. For 2 moles of $\text{H}^+$, a strong acid would liberate $2 \times 55.84 = 111.68\text{ kJ}$. Actual heat released is 106.68 kJ. The difference is the ionization enthalpy: $111.68 - 106.68 = 5.0\text{ kJ/mol}$.