Enthalpy of neutralization of the reaction between and is –13.2 kcal/eq and that of the reaction bet — Thermodynamics and Thermochemistry Chemistry Question
Question
Enthalpy of neutralization of the reaction between $\text{CH}_3\text{COOH(aq)}$ and $\text{NaOH(aq)}$ is –13.2 kcal/eq and that of the reaction between $\text{H}_2\text{SO}_4\text{(aq)}$ and $\text{KOH(aq)}$ is –13.7 kcal/eq. The enthalpy of dissociation of $\text{CH}_3\text{COOH(aq)}$ is
Answer: B
💡 Solution & Explanation
The neutralization of a strong acid/strong base yields –13.7 kcal/eq. The weak acid yields less heat (–13.2 kcal/eq). The difference is the endothermic heat consumed to dissociate the weak acid: $\Delta H_{\text{dissociation}} = 13.7 - 13.2 = +0.5\text{ kcal/eq}$.
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