Under identical conditions, how many millilitres of 1 M-KOH and 2 M- solutions are required to produ — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

Maximum temperature rise occurs when moles of $\text{H}^+$ exactly equal moles of $\text{OH}^-$. Let $x$ be mL of KOH and $y$ be mL of $\text{H}_2\text{SO}_4$. $x + y = 100$. Moles of $\text{OH}^- = 1 \times x$. Moles of $\text{H}^+ = 2 \times 2 \times y = 4y$. Setting $x = 4y \implies 4y + y = 100 \implies 5y = 100 \implies y = 20\text{ mL}$. Thus $x = 80\text{ mL}$.