A geyser, operating on LPG (liquefied petroleum gas) heats water flowing at the rate of 3.0 litres per minutes, from to . If the heat of combustion of LPG is 40,000 J/g, how much fuel, in g, is consum

Question

A geyser, operating on LPG (liquefied petroleum gas) heats water flowing at the rate of 3.0 litres per minutes, from $27^\circ	ext{C}$ to $77^\circ	ext{C}$. If the heat of combustion of LPG is 40,000 J/g, how much fuel, in g, is consumed per minute? (Specific heat capacity of water is 4200 J/kg-K)

Prashant Kotian · Accepted Answer

Correct answer: C. Mass of water per minute = . Temperature rise = . Heat required per minute . Fuel consumed = .

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