The enthalpy change involved in the oxidation of glucose is β2880 kJ/mol. Twenty five per cent of th β Thermodynamics and Thermochemistry Chemistry Question
Question
The enthalpy change involved in the oxidation of glucose is β2880 kJ/mol. Twenty five per cent of this energy is available for muscular work. If 100 kJ of muscular work is needed to walk 1 km, what is the maximum distance that a person will be able to walk after eating 120 g of glucose?
Answer: D
π‘ Solution & Explanation
Moles of glucose = $120\text{ g} / 180\text{ g/mol} = 2/3\text{ mol}$. Total energy released = $(2/3) \times 2880 = 1920\text{ kJ}$. Energy available for work = $25\% \text{ of } 1920 = 480\text{ kJ}$. Distance = $480\text{ kJ} / 100\text{ kJ/km} = 4.8\text{ km}$.
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