The enthalpy of combustion of methane is –890 kJ. The volume of methane at and 1 atm to be burnt to — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

Number of moles required to produce 2670 kJ is $n = 2670 / 890 = 3\text{ moles}$. Under Standard Temperature and Pressure ($0^\circ\text{C}$, 1 atm), 1 mole of an ideal gas occupies 22.4 L. Volume = $3 \times 22.4\text{ L} = 67.2\text{ L}$.