Given enthalpy of formation of and are –94.0 kJ and –152 kJ, respectively, and the enthalpy of the r — Thermodynamics and Thermochemistry Chemistry Question
Question
Given enthalpy of formation of $\text{CO}_2\text{(g)}$ and $\text{CaO(s)}$ are –94.0 kJ and –152 kJ, respectively, and the enthalpy of the reaction: $\text{CaCO}_3\text{(s)} \to \text{CaO(s)} + \text{CO}_2\text{(g)}$ is 42 kJ. The enthalpy of formation of $\text{CaCO}_3\text{(s)}$ is
Answer: D
💡 Solution & Explanation
$\Delta H_{rxn} = \Delta H_f(\text{CaO}) + \Delta H_f(\text{CO}_2) - \Delta H_f(\text{CaCO}_3) \implies 42 = -152 - 94.0 - \Delta H_f(\text{CaCO}_3) \implies 42 = -246 - \Delta H_f(\text{CaCO}_3) \implies \Delta H_f(\text{CaCO}_3) = -246 - 42 = -288\text{ kJ/mol}$.
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