The value of of is –853.5 kJ mol. for the reaction: , is –76.00 kJ. The value of of is — Thermodynamics and Thermochemistry Chemistry Question
Question
The value of $\Delta_f H^\circ$ of $\text{U}_3\text{O}_8\text{(s)}$ is –853.5 kJ mol$^{-1}$. $\Delta H^\circ$ for the reaction: $3\text{UO}_2\text{(s)} + \text{O}_2\text{(g)} \to \text{U}_3\text{O}_8\text{(s)}$, is –76.00 kJ. The value of $\Delta_f H^\circ$ of $\text{UO}_2\text{(s)}$ is
Answer: A
💡 Solution & Explanation
$\Delta H_{rxn} = \Delta H_f(\text{U}_3\text{O}_8) - 3\Delta H_f(\text{UO}_2) \implies -76.00 = -853.5 - 3\Delta H_f(\text{UO}_2) \implies 3\Delta H_f(\text{UO}_2) = -853.5 + 76.00 = -777.5\text{ kJ}$. $\Delta H_f(\text{UO}_2) = -259.17\text{ kJ/mol}$.
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