The enthalpy of formation of HCl(g) from the following reaction:<br> is — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

The equation implies 44 kcal of heat is released as a product ($\Delta H = -44\text{ kcal}$) for the formation of 2 moles of HCl. Enthalpy of formation is per mole, so $\Delta H_f = -44 / 2 = -22\text{ kcal/mol}$.