The enthalpy of formation of HCl(g) from the following reaction:<br> is — Thermodynamics and Thermochemistry Chemistry Question
Question
The enthalpy of formation of HCl(g) from the following reaction:<br>$\text{H}_2\text{(g)} + \text{Cl}_2\text{(g)} \to 2\text{HCl(g)} + 44\text{ kcal}$ is
Answer: B
💡 Solution & Explanation
The equation implies 44 kcal of heat is released as a product ($\Delta H = -44\text{ kcal}$) for the formation of 2 moles of HCl. Enthalpy of formation is per mole, so $\Delta H_f = -44 / 2 = -22\text{ kcal/mol}$.
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