Thermodynamics and ThermochemistryhardMCQ SINGLE

The vapour pressures of water and ice at are 0.28 and 0.26 Pa, respectively. What is the free energyThermodynamics and Thermochemistry Chemistry Question

Question

The vapour pressures of water and ice at $-10^\circ\text{C}$ are 0.28 and 0.26 Pa, respectively. What is the free energy change for the process? $\text{H}_2\text{O (l, } -10^\circ\text{C, 0.28 Pa, 1 mole)} \to \text{H}_2\text{O (s, } -10^\circ\text{C, 0.26 Pa, 1 mole)}$

Answer: B

💡 Solution & Explanation

The initial and final states are respective equilibrium boundaries where $\Delta G_{\text{phase}} = 0$. The overall $\Delta G$ equates to the reversible isothermal expansion of the vapor from 0.28 Pa to 0.26 Pa. $\Delta G = nRT \ln(P_2/P_1) = 1 \times R \times 263 \times \ln(0.26/0.28) = R \times 263 \times \ln\left(\frac{13}{14}\right)$.

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