The entropy change accompanying the transfer of 12,000 J of heat from a body A at to a body B at is — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

The absolute temperatures are $T_A = 600 \text{ K}$ and $T_B = 400 \text{ K}$. Entropy change of source A is $\Delta S_A = -\frac{12000}{600} = -20 \text{ J/K}$. Entropy change of sink B is $\Delta S_B = +\frac{12000}{400} = +30 \text{ J/K}$. The total entropy change is $\Delta S_{\text{total}} = -20 + 30 = +10.0 \text{ J/K}$.