One mole of an ideal gas with the adiabatic exponent '' goes through a polytropic process as a resul — Thermodynamics and Thermochemistry Chemistry Question
Question
One mole of an ideal gas with the adiabatic exponent '$\gamma$' goes through a polytropic process as a result of which the absolute temperature of the gas increases $\tau$-fold. The polytropic constant equals $n$. The entropy increment of the gas in this process is
Answer: A
💡 Solution & Explanation
Molar heat capacity for a polytropic process is $C = C_V + \frac{R}{1-n} = \frac{R}{\gamma-1} - \frac{R}{n-1} = \frac{R(n-1) - R(\gamma-1)}{(\gamma-1)(n-1)} = \frac{R(n-\gamma)}{(\gamma-1)(n-1)}$. $\Delta S = \int \frac{C}{T} dT = C \ln\left(\frac{T_2}{T_1}\right) = \frac{R(n-\gamma)}{(\gamma-1)(n-1)} \ln\tau$.
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