Thermodynamics and ThermochemistrymediumMCQ SINGLE

An amount of 2 mole of CO was in the small cubical container of length, () at . The gas was taken ouThermodynamics and Thermochemistry Chemistry Question

Question

An amount of 2 mole of CO was in the small cubical container of length, ($l = a$) at $57^\circ\text{C}$. The gas was taken out completely from the small container and put into large container ($l = 2a$) at the same temperature. What is the change in entropy, if it is assumed that the process is reversible and gas is behaving as an ideal gas?

Answer: A

💡 Solution & Explanation

Initial volume $V_1 = a^3$, final volume $V_2 = (2a)^3 = 8a^3$. The process is isothermal expansion. $\Delta S = n R \ln\left(\frac{V_2}{V_1}\right) = 2 \times 8.314 \times \ln(8) = 16.628 \times 2.079 = 34.58 \text{ J/K}$.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry