One mole of an ideal monoatomic gas is heated in a process . By what amount heat is absorbed in the — Thermodynamics and Thermochemistry Chemistry Question
Question
One mole of an ideal monoatomic gas is heated in a process $P V^{5/2} = \text{constant}$. By what amount heat is absorbed in the process in $26^\circ\text{C}$ rise in temperature?
Answer: B
💡 Solution & Explanation
Polytropic process $n=5/2$. Molar heat capacity $C = C_V + \frac{R}{1-n} = 1.5R + \frac{R}{1 - 2.5} = 1.5R - 0.667R = \frac{5}{6}R$. Heat absorbed $Q = 1 \times \frac{5}{6} \times 8.314 \times 26 \approx 180.1\text{ J}$.
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