The average degree of freedom per molecule for a gas is 6. The gas performs 25 J of work when it exp — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

With $f=6$, $C_V = \frac{6}{2}R = 3R$ and $C_P = 4R$. Heat at constant pressure $Q = nC_P\Delta T = 4nR\Delta T$. The work done $W = nR\Delta T = 25\text{ J}$. Consequently, heat absorbed is $Q = 4 \times 25\text{ J} = 100\text{ J}$.