A container of volume is divided into two equal parts by a partition. One part has an ideal diatomic — Thermodynamics and Thermochemistry Chemistry Question
Question
A container of volume $1 \text{ m}^3$ is divided into two equal parts by a partition. One part has an ideal diatomic gas at 300 K and the other part has vacuum. The whole system is isolated from the surrounding. When the partition is removed, the gas expands to occupy the whole volume. Its temperature will be
Answer: A
💡 Solution & Explanation
Expansion against a vacuum dictates external pressure is zero, hence $W = 0$. Since isolated, $Q = 0$, giving $\Delta U = 0$ resulting in $\Delta T = 0$ for an ideal gas. Temperature remains exactly 300 K.
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