Heat energy of 743 J is needed to raise the temperature of 5 moles of an ideal gas by 2 K at constan — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

$Q_P = n C_p \Delta T \implies 743 = 5 \times C_p \times 2 \implies C_p = 74.3 \text{ J/mol-K}$. From $C_v = C_p - R = 74.3 - 8.314 = 65.986 \text{ J/mol-K}$. The required heat $Q_V = n C_v \Delta T = 5 \times 65.986 \times 2 = 659.86 \text{ J} \approx 660 \text{ J}$.