One mole of oxygen is heated from , at constant pressure, till its volume increased by 10%. The spec — Thermodynamics and Thermochemistry Chemistry Question
Question
One mole of oxygen is heated from $0^\circ\text{C}$, at constant pressure, till its volume increased by 10%. The specific heat of oxygen, under these conditions, is $0.22 \text{ cal/g-K}$. The amount of heat required is
Answer: A
💡 Solution & Explanation
At constant P, $V \propto T$. A 10% volume increase dictates a 10% temperature increase from 273 K, so $\Delta T = 27.3 \text{ K}$. Total mass $m = 32 \text{ g}$. $Q = mc\Delta T = 32 \times 0.22 \times 27.3 \text{ cal}$. Converting to Joules yields $32 \times 0.22 \times 27.3 \times 4.2 \text{ J}$.
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