Work done by a sample of an ideal gas in a process A is double the work done in another process B. T — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

Since $\Delta T$ is equal, $\Delta U$ is equal for both. $Q = \Delta U + W$. The molar heat capacity $C = Q / (n\Delta T) = (\Delta U + W)/(n\Delta T)$. Since $W_A = 2W_B$, the total heat supplied in process A is greater, dictating $C_A > C_B$.