Two moles of an ideal monoatomic gas is heated from to , reversibly and isochorically. The entropy o — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

Isochoric heating ($\Delta V = 0$). $\Delta S = n C_v \ln(T_2/T_1)$. $n=2$, $C_v = \frac{3}{2}R$ (monoatomic). $T_1 = 300\text{ K}$, $T_2 = 900\text{ K}$. $\Delta S = 2 \times \frac{3}{2}R \ln(900/300) = 3R \ln 3$. Increases by $3R \ln 3$.