The entropy change in the fusion of one mole of a solid melting at 300 K (latent heat of fusion, 293 — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

$\Delta S_{fusion} = \frac{\Delta H_{fusion}}{T_m} = \frac{2930\text{ J/mol}}{300\text{ K}} = 9.766\text{ J/K-mol} \approx 9.77\text{ J/K-mol}$.