When one mole of an ideal gas is compressed to half of its initial volume and simultaneously heated — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

$\Delta S = C_v \ln(T_2/T_1) + R \ln(V_2/V_1)$. Substituting $T_2 = 2T_1$ and $V_2 = 0.5 V_1$, we get $\Delta S = C_v \ln(2) + R \ln(0.5) = C_v \ln(2) - R \ln(2) = (C_v - R) \ln 2$.