One mole of a non-ideal gas undergoes a change of state (2 atm, 3 L, 95 K) (4 atm, 5 L, 245 K) with — Thermodynamics and Thermochemistry Chemistry Question
Question
One mole of a non-ideal gas undergoes a change of state (2 atm, 3 L, 95 K) $\to$ (4 atm, 5 L, 245 K) with a change in internal energy, $\Delta U = 30.0$ L-atm. The change in enthalpy ($\Delta H$) of the process in L-atm is
Answer: C
💡 Solution & Explanation
Enthalpy is defined by $H = U + PV$. The change in enthalpy evaluates as $\Delta H = \Delta U + \Delta (PV) = \Delta U + (P_2V_2 - P_1V_1) = 30.0 + (4 \times 5 - 2 \times 3) = 30.0 + (20 - 6) = 30.0 + 14 = 44.0 \text{ L-atm}$.
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