Thermodynamics and ThermochemistrymediumMCQ SINGLE

What is the change in internal energy when a gas contracts from 325 ml to 125 ml at a constant pressThermodynamics and Thermochemistry Chemistry Question

Question

What is the change in internal energy when a gas contracts from 325 ml to 125 ml at a constant pressure of 2 bar, while at the same time being cooled by removing 124 J heat?

Answer: B

💡 Solution & Explanation

By the First Law, $\Delta U = q + W$. Heat removed $q = -124 \text{ J}$. Work done on the gas during contraction $W = -P \Delta V = -2 \text{ bar} \times (125 - 325) \times 10^{-3} \text{ L} = -2 \times (-0.2) \text{ bar L} = 0.4 \text{ bar L}$. Converting to Joules ($1 \text{ bar L} = 100 \text{ J}$), $W = 40 \text{ J}$. $\Delta U = -124 \text{ J} + 40 \text{ J} = -84 \text{ J}$.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry