The minimum work which must be done to compress 16 g of oxygen isothermally, at 300 K from a pressur — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

Moles of $\text{O}_2$, $n = 16\text{ g} / 32\text{ g/mol} = 0.5\text{ mol}$. Minimum work of compression is reversible work. $W = nRT \ln(P_2/P_1) = 0.5 \times 8.3 \times 300 \times \ln(100) = 1245 \times 4.6 = 5727\text{ J}$.