Five moles of an ideal gas expand isothermally and reversibly from an initial pressure of 100 atm to — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

Reversible isothermal work magnitude $W = nRT \ln(P_1/P_2)$. Using $R \approx 2\text{ cal/K-mol}$, $T = 300\text{ K}$, $n = 5$. Work done $= 5 \times 2 \times 300 \times \ln(100/1) = 3000 \times 4.6 = 13800\text{ cal}$.