In a given process on an ideal gas, and . Then for the gas, — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

Since $dw = 0$, the process is isochoric ($\Delta V = 0$). By First Law, $dU = dq + dw = dq$. Because $dq < 0$, $dU$ is negative. For an ideal gas, $dU = nC_v dT$, so a decrease in internal energy directly corresponds to a decrease in temperature.