The volume of a system becomes twice its original volume on the absorption of 300 cal of heat. The w — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

Heat absorbed $q = +300\text{ cal}$. Work done *on the surrounding* means work done *by* the system, so $w = -200\text{ cal}$. Internal energy change $\Delta U = q + w = 300 - 200 = 100\text{ cal}$.