The normal boiling point of a liquid is 350 K and is 35 kJ/mol. Assume that is independent from temp — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

At 1 atm and 350 K, equilibrium exists: $\Delta S_{\text{vap}} = \frac{35000}{350} = 100\text{ J/K-mol}$. At 0.5 atm, vaporization is highly spontaneous ($\Delta G < 0$) and the gaseous volume is larger, creating higher entropy ($\Delta S > 100$). At 2.0 atm, 350 K is below the new boiling point, rendering vaporization non-spontaneous ($\Delta G > 0$).