Match the process of Column I with entropy or enthalpy change in Column II — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

(A) $\Delta n_g = 0 \implies \Delta S \approx 0$ (P); it's an endothermic formation ($\Delta H > 0$, R). (B) Complex formation reduces particle count ($\Delta S < 0$, Q) and is exothermic ($\Delta H < 0$, S). (C) Decomposition is endothermic ($\Delta H > 0$, R) and generates more gas molecules ($\Delta S > 0$, absent). (D) Solidification from gases drops entropy ($\Delta S < 0$, Q) and releases lattice energy ($\Delta H < 0$, S).