Thermodynamics and ThermochemistrymediumCOMPREHENSIVE

for the reaction isThermodynamics and Thermochemistry Chemistry Question

Question

$\Delta G^\circ$ for the reaction is

Answer: A

💡 Solution & Explanation

$\Delta H = \Delta E + \Delta n_g RT = 2.1\text{ kcal} + (2 \times 2 \times 298 / 1000)\text{ kcal} = 2.1 + 1.192 = 3.292\text{ kcal}$. $\Delta G = \Delta H - T\Delta S = 3.292 - (298 \times 20 / 1000) = 3.292 - 5.96 = -2.668\text{ kcal}$, which evaluates to approximately $-2.7\text{ kcal}$.

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