What is the flow of and at valve-1? — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

Since $1000\text{ mol/sec}$ of $\text{CH}_3\text{OH}$ is formed and it strictly represents $2/3$ of the total CO, the total input CO generated by the reformer is $1500\text{ mol/sec}$. Because the reformer yields exactly $3\text{ moles}$ of $\text{H}_2$ for every $1\text{ mole}$ of CO, the $\text{H}_2$ output is strictly $3 \times 1500 = 4500\text{ mol/sec}$.