What will be the maximum temperature (approximately) attained if the process occurs in adiabatic con — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

Reaction: $\text{H}_2 + 0.5\text{O}_2 + 2\text{N}_2 \to \text{H}_2\text{O} + 2\text{N}_2$. Since it's a rigid vessel ($V$ is constant), use $C_v = C_p - R \approx C_p - 2$. $C_v(\text{N}_2) = 6.3\text{ cal/K}$, $C_v(\text{H}_2\text{O}) = 9.3\text{ cal/K}$. Total $C_v = 9.3 + 2(6.3) = 21.9\text{ cal/K}$. Heat released $= 57.8\text{ kcal} = 57800\text{ cal}$. $\Delta T = 57800 / 21.9 \approx 2639\text{ K}$. $T_{\text{max}} = 298\text{ K} + 2639\text{ K} = 2937\text{ K} \approx 2940\text{ K}$.