The bond enthalpy of bond (kJ/mol) is — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

For acetonitrile ($\text{CH}_3\text{CN}$): $\Delta H_{\text{atomization}} = 2(719) + 1.5(435) + 0.5(948) - 88 = 1438 + 652.5 + 474 - 88 = 2476.5\text{ kJ/mol}$. $\text{CH}_3\text{CN}$ possesses 3 C-H, 1 C-C, and 1 $\text{C}\equiv\text{N}$ bond. $3(414) + 335 + E_{\text{C}\equiv\text{N}} = 2476.5 \implies 1242 + 335 + E_{\text{C}\equiv\text{N}} = 2476.5 \implies E_{\text{C}\equiv\text{N}} = 899.5\text{ kJ/mol}$.