The change in enthalpy of gas in Section A is — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

Taking $n = 10\text{ moles}$ structurally if utilizing the raw 27.3 K text (or $n=1$ with scaled factors), $\Delta H = n C_p \Delta T$. For $n=10$, $C_p = \frac{5}{2}R \approx 5\text{ cal/K-mol}$. $\Delta T = 1638 - 27.3 = 1610.7\text{ K}$. $\Delta H = 10 \times 5 \times 1610.7 = 80535\text{ cal} = 80.53\text{ kcal}$.