What is the magnitude of work performed by the gas? — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

Work done $W = \int_{V_1}^{V_2} P dV = \int_{V_0}^{4V_0} \alpha V dV = \frac{\alpha}{2} \left[ (4V_0)^2 - (V_0)^2 \right] = \frac{\alpha}{2} [16V_0^2 - V_0^2] = \frac{15\alpha V_0^2}{2}$.