The van der Waal's constants for three gases R, S and T are given below <br><br>Gas | | <br>R | 5.2 — States of Matter and Gaseous State Chemistry Question
Question
The van der Waal's constants for three gases R, S and T are given below <br><br>Gas | $a\text{ (atm L}^2\text{/mol}^2\text{)}$ | $b\text{ (L/mol)}$<br>R | 5.2 | 0.420<br>S | 3.8 | 0.038<br>T | 2.3 | 0.032<br><br>The correct sequence of placing the easily liquefiable gas last and the one difficult to liquefy first is
Answer: C
💡 Solution & Explanation
Ease of liquefaction fundamentally depends directly on the strength of intermolecular attractive forces, captured primarily by constant '$a$'. Lighter forces (lower $a$) make a gas harder to liquefy. Order of $a$: T (2.3) < S (3.8) < R (5.2). The sequence starting with the most difficult (lowest $a$) is T, S, R. Therefore, correct answer is C.
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