For a certain gas obeying van der Waal's equation, the critical temperature is 305.5 K and the criti — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

Using the universal critical compressibility factor for a van der Waals gas $Z_c = \frac{P_c V_c}{R T_c} = \frac{3}{8}$. Solving for $V_c = \frac{3 R T_c}{8 P_c} = \frac{3 \times 0.0821 \times 305.5}{8 \times 48.2} \approx \frac{75.24}{385.6} = 0.195\text{ l}$. Therefore, correct answer is B.