Pressure of 1 g of an ideal gas A at 27°C is found to be 2 bar. When 2 g of another ideal gas B is introduced in the same flask at same temperature the pressure becomes 3 bar. What is the relationship

Question

Pressure of 1 g of an ideal gas A at 27°C is found to be 2 bar. When 2 g of another ideal gas B is introduced in the same flask at same temperature the pressure becomes 3 bar. What is the relationship between their molecular masses?

Prashant Kotian · Accepted Answer

Correct answer: C. PA = 2 bar, PB = 1 bar. PA/PB = (mA/MA) / (mB/MB) = (1/MA) / (2/MB) = MB / 2MA. 2/1 = MB/2MA implies MB = 4MA. Therefore, correct answer is C.

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