The minimum pressure needed for liquefaction of gas at the temperature calculated above, is | States of Matter and Gaseous State — Chem-Mantra | Chem-Mantra

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States of Matter and Gaseous StatehardCOMPREHENSIVE

Question

The minimum pressure needed for liquefaction of gas at the temperature calculated above, is

Answer: C

💡 Solution & Explanation

Substituting $V_c$ and $T_c$ back into state equation yields $P_c = \sqrt{aR / 216b^3}$. Therefore, correct answer is C.

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