Flask with greater mean free path for the molecules () — States of Matter and Gaseous State Chemistry Question
Question
Flask with greater mean free path for the molecules ($r_{\text{H}_2} : r_{\text{CH}_4} : r_{\text{O}_2} = 1 : 2 : 2$)
Answer: C
💡 Solution & Explanation
Mean free path $\lambda \propto 1 / (N \sigma^2) \propto M / \sigma^2$. A ($2/1=2$), B ($16/4=4$), C ($32/4=8$). Flask C is highest. Therefore, correct answer is C.
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