At what temperature, the speeds of nitrogen gas molecules at m/s and m/s, are associated with equal — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

Equating $f(300) = f(600)$ yields $(600/300)^2 = e^{M(600^2 - 300^2)/2RT} \implies 4 = e^{270000 M / 2RT}$. Taking log gives $T = 337.5 \text{ K} = 64.5^\circ\text{C}$. Therefore, correct answer is C.