What percentage of liquid water will vaporize? — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

Maximum vapor pressure is 0.04 atm. Moles of vapor $n = \frac{0.04 \times 40000}{0.08 \times 300} = 66.67 \text{ mol}$. Mass vaporized $= 66.67 \times 18 = 1200 \text{ g} = 1.2 \text{ kg}$. Percentage $= (1.2 / 5.0) \times 100 = 24\%$. Therefore, correct answer is B.