When gases C and D were passed through a hot tube of powdered copper, gas C reacted to form CuO. The — States of Matter and Gaseous State Chemistry Question
Question
When gases C and D were passed through a hot tube of powdered copper, gas C reacted to form CuO. The remaining gas, D, was collected in a third 821 ml flask and found to have mass of 1.68 g and a pressure of 1.8 atm at 27°C. How many moles each of C and D were present and what are their likely identities?
Answer: A
💡 Solution & Explanation
C reacts with Cu to form CuO, so C is O₂. D remaining at 300 K: $n_D = (1.8 \times 0.821) / (0.0821 \times 300) = 0.06 \text{ mol}$. Molar mass of D = $1.68 / 0.06 = 28 \text{ g/mol}$ (N₂). Moles of C = $0.07 - 0.06 = 0.01 \text{ mol}$. Therefore, correct answer is A.
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