What is the volume occupied by 2 mole of a perfect gas at 2 atm and 66.67°N? — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

Absolute temperature $T_{abs} = 66.67 + 233.33 = 300^\circ\text{N}_{abs}$. Volume $V = nRT/P = 2 \times 0.12 \times 300 / 2 = 36 \text{ l}$. Therefore, correct answer is A.