**Match the reactions in Column I with Column II (JEE Archive):** <br> **Column I:** <br> (A) <br> ( — Redox Reactions and Volumetric Analysis Chemistry Question
Question
**Match the reactions in Column I with Column II (JEE Archive):** <br> **Column I:** <br> (A) $NH_4NO_3 \xrightarrow{\Delta} N_2O + 2H_2O$ <br> (B) $NH_4NO_2 \xrightarrow{\Delta} N_2 + 2H_2O$ <br> (C) $PCl_5 \xrightarrow{\Delta} PCl_3 + Cl_2$ <br> (D) $3Cl_2 + 6OH^- \rightarrow 5Cl^- + ClO_3^- + 3H_2O$ <br> **Column II:** <br> (p) Intramolecular redox <br> (q) Disproportionation <br> (r) Decomposition <br> (s) Redox reaction
💡 Solution & Explanation
**Logic:** <br> (A/B) The same molecule contains the oxidant ($NO_3^- / NO_2^-$) and reductant ($NH_4^+$). It's intramolecular redox and thermal decomposition. <br> (C) $PCl_5$ decomposes. $P$ remains +5, but $Cl$ goes from -1 to 0 (oxidation) and -1 (Wait, $P$ is +5 in both; however $Cl$ in $Cl_2$ is 0. This is redox). <br> (D) $Cl_2$ (0) goes to -1 and +5 (Disproportionation).