Redox Reactions and Volumetric AnalysishardMATCH FOLLOWING

**Match Column I (Species) with Column II (Possible redox behavior):** <br> (Multiple matches possibRedox Reactions and Volumetric Analysis Chemistry Question

Question

**Match Column I (Species) with Column II (Possible redox behavior):** <br> (Multiple matches possible) <br> **Column I:** <br> (A) $H_2O_2$ <br> (B) $SO_2$ <br> (C) $MnO_4^-$ <br> (D) $I^-$ <br> **Column II:** <br> (p) Oxidising Agent <br> (q) Reducing Agent <br> (r) Disproportionation <br> (s) Bleaching Agent

Answer: A

💡 Solution & Explanation

**Logic:** <br> (A) $H_2O_2$ (-1) can go to 0 (RA) or -2 (OA). It disproportionates to $H_2O + O_2$. It bleaches via oxidation. <br> (B) $SO_2$ (+4) can go to +6 (RA) or 0 (OA). It disproportionates in some conditions. It bleaches via reduction. <br> (C) $MnO_4^-$ (+7) is in max O.S., acts only as OA. <br> (D) $I^-$ (-1) is in min O.S., acts only as RA.

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