**Match Column I (Titration) with Column II (Relationship at equivalence point):** <br> **Column I:* — Redox Reactions and Volumetric Analysis Chemistry Question
Question
**Match Column I (Titration) with Column II (Relationship at equivalence point):** <br> **Column I:** <br> (A) $NaOH + H_2SO_4$ <br> (B) $KMnO_4 + FeSO_4$ (acidic) <br> (C) $K_2Cr_2O_7 + SnCl_2$ (acidic) <br> (D) $Na_2CO_3 + HCl$ (Methyl orange) <br> **Column II:** <br> (p) $M_1 V_1 = 2 M_2 V_2$ <br> (q) $5 M_1 V_1 = M_2 V_2$ <br> (r) $6 M_1 V_1 = 2 M_2 V_2$ <br> (s) $M_1 V_1 = M_2 V_2$
💡 Solution & Explanation
**Logic:** <br> (A) $n_1 M_1 V_1 = n_2 M_2 V_2 \Rightarrow 1 M_1 V_1 = 2 M_2 V_2$ (where 2 is for $H_2SO_4$). <br> (B) $5 M_1 V_1 = 1 M_2 V_2$ ($n=5$ for $KMnO_4$, $n=1$ for $Fe^{2+}$). <br> (C) $6 M_1 V_1 = 2 M_2 V_2$ ($n=6$ for $K_2Cr_2O_7$, $n=2$ for $Sn^{2+}$). <br> (D) $n=2$ for $Na_2CO_3$ at MeOH endpoint, $n=1$ for $HCl \Rightarrow 2 M_1 V_1 = 1 M_2 V_2$.