**Match Column I (Species) with Column II (Oxidation state of the central metal atom):** <br> **Colu — Redox Reactions and Volumetric Analysis Chemistry Question
Question
**Match Column I (Species) with Column II (Oxidation state of the central metal atom):** <br> **Column I:** <br> (A) $[Fe(H_2O)_5NO]SO_4$ <br> (B) $K_3[Fe(CN)_6]$ <br> (C) $K_4[Fe(CN)_6]$ <br> (D) $Fe(CO)_5$ <br> **Column II:** <br> (p) +2 <br> (q) +3 <br> (r) +1 <br> (s) 0
Answer: A
💡 Solution & Explanation
**Logic:** <br> (A) In the brown ring complex, $NO$ is $NO^+$, making $Fe$ have an O.S. of +1. <br> (B) $[Fe(CN)_6]^{3-}$: $x + 6(-1) = -3 \Rightarrow x = +3$. <br> (C) $[Fe(CN)_6]^{4-}$: $x + 6(-1) = -4 \Rightarrow x = +2$. <br> (D) Metal carbonyls have the metal in zero oxidation state.
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